tup1 = 1, 2, 3
print tup1
# 嵌套元组
tup2 = (1, 2, 3), (4, 5)
print tup2
(1, 2, 3)
((1, 2, 3), (4, 5))
l = [1, 2, 3]
print tuple(l)
str = 'Hello ChinaHadoop'
print tuple(str)
(1, 2, 3)
('H', 'e', 'l', 'l', 'o', ' ', 'C', 'h', 'i', 'n', 'a', 'H', 'a', 'd', 'o', 'o', 'p')
tup3 = tuple(str)
print tup3[4]
o
tup1 + tup2
(1, 2, 3, (1, 2, 3), (4, 5))
a, b, c = tup1
print b
2
# 函数返回多个值
def return_multiple():
t = (1, 2, 3)
return t
a, _, c = return_multiple()
print c
3
# 元组列表迭代
tuple_lst = [(1, 2), (3, 4), (5, 6)]
for x, y in tuple_lst:
print x+y
3
7
11
tup3.count('o')
3
lst_1 = [1, 2, 3, 'a', 'b', (4, 5)]
print lst_1
lst_2 = range(1, 9)
print lst_2
[1, 2, 3, 'a', 'b', (4, 5)]
[1, 2, 3, 4, 5, 6, 7, 8]
lst_3 = list(tup3)
print lst_3
['H', 'e', 'l', 'l', 'o', ' ', 'C', 'h', 'i', 'n', 'a', 'H', 'a', 'd', 'o', 'o', 'p']
lst_4 = range(10)
# 末尾添加
lst_4.append(11)
print lst_4
# 指定位置插入
lst_4.insert(5, 12)
print lst_4
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11]
[0, 1, 2, 3, 4, 12, 5, 6, 7, 8, 9, 11]
# 删除指定位置的元素并返回
item = lst_4.pop(6)
print item
print lst_4
5
[0, 1, 2, 3, 4, 12, 6, 7, 8, 9, 11]
# 删除指定的值，注意12在这里是“值”不是“位置”
lst_4.remove(12)
print lst_4
[0, 1, 2, 3, 4, 6, 7, 8, 9, 11]
lst_3 = lst_1 + lst_2
print lst_3
lst_1.extend(lst_2)
print lst_1
[1, 2, 3, 'a', 'b', (4, 5), 1, 2, 3, 4, 5, 6, 7, 8]
[1, 2, 3, 'a', 'b', (4, 5), 1, 2, 3, 4, 5, 6, 7, 8]
import random
lst_5 = range(10)
random.shuffle(lst_5)
print lst_5
[8, 1, 7, 3, 0, 5, 9, 6, 4, 2]
lst_5.sort()
print lst_5
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
lst_6 = ['Welcome', 'to', 'Python', 'Data', 'Analysis', 'Course']
lst_6.sort()
print lst_6
['Analysis', 'Course', 'Data', 'Python', 'Welcome', 'to']
lst_6.sort(key = len, reverse=True)
print lst_6
['Analysis', 'Welcome', 'Course', 'Python', 'Data', 'to']
print lst_5
print lst_5[1:5]
print lst_5[5:]
print lst_5[:5]
print lst_5[-5:]
print lst_5[-5:-2]
print lst_5[::2]
print lst_5[::-1]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4]
[5, 6, 7, 8, 9]
[0, 1, 2, 3, 4]
[5, 6, 7, 8, 9]
[5, 6, 7]
[0, 2, 4, 6, 8]
[9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
lst_6 = ['Welcome', 'to', 'Python', 'Data', 'Analysis', 'Course'] # (0, 'Welcome')
for i, item in enumerate(lst_6):
print '%i-%s' %(i, item)
0-Welcome
1-to
2-Python
3-Data
4-Analysis
5-Course
str_dict = dict((i, item) for i, item in enumerate(lst_6))
print str_dict
{0: 'Welcome', 1: 'to', 2: 'Python', 3: 'Data', 4: 'Analysis', 5: 'Course'}
import random
lst_5 = range(10)
random.shuffle(lst_5)
print lst_5
#sorted
lst_5_sorted = sorted(lst_5)
print lst_5
print lst_5_sorted
[3, 6, 5, 1, 0, 8, 9, 7, 4, 2]
[3, 6, 5, 1, 0, 8, 9, 7, 4, 2]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
lst_6 = ['Welcome', 'to', 'Python', 'Data', 'Analysis', 'Course']
lst_7 = range(5) #[0, 1, 2, 3, 4]
lst_8 = ['a', 'b', 'c']
zip_lst = zip(lst_6, lst_8, lst_7)
print zip_lst
[('Welcome', 'a', 0), ('to', 'b', 1), ('Python', 'c', 2)]
zip(*zip_lst)
[('Welcome', 'to', 'Python'), ('a', 'b', 'c'), (0, 1, 2)]
list(reversed(lst_6))
['Course', 'Analysis', 'Data', 'Python', 'to', 'Welcome']
empty_dict = {}
dict1 = {'a': 1, 2: 'b', '3': [1, 2, 3]}
print empty_dict
print dict1
{}
{'a': 1, 2: 'b', '3': [1, 2, 3]}
dict1[4] = (4, 5)
print dict1
{'a': 1, 2: 'b', 4: (4, 5), '3': [1, 2, 3]}
del dict1[2]
print dict1
{'a': 1, 4: (4, 5), '3': [1, 2, 3]}
a_value = dict1.pop('a')
print a_value
print dict1
1
{4: (4, 5), '3': [1, 2, 3]}
print dict1.keys()
print dict1.values()
[4, '3']
[(4, 5), [1, 2, 3]]
dict2 = {4: 'new1', 5: 'news'}
dict1.update(dict2)
print dict1
{'3': [1, 2, 3], 4: 'new1', 5: 'news'}
# 普通方法
dict_3 = {}
l1 = range(10)
l2 = list(reversed(range(10)))
for i1, i2 in zip(l1, l2):
dict_3[i1] = i2
print dict_3
{0: 9, 1: 8, 2: 7, 3: 6, 4: 5, 5: 4, 6: 3, 7: 2, 8: 1, 9: 0}
dict_4 = dict(zip(l1, l2))
print dict_4
{0: 9, 1: 8, 2: 7, 3: 6, 4: 5, 5: 4, 6: 3, 7: 2, 8: 1, 9: 0}
hash(12)
12
hash('test hash')
-520327859
hash((1, 2, 3))
-378539185
hash([1, 2, 3])
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-38-0b995650570c> in <module>()
----> 1 hash([1, 2, 3])
TypeError: unhashable type: 'list'
a = set(range(10))
print a
b = set(range(5,15))
print b
set([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])
set([5, 6, 7, 8, 9, 10, 11, 12, 13, 14])
a | b
{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}
a & b
{5, 6, 7, 8, 9}
a - b
{0, 1, 2, 3, 4}
a ^ b
{0, 1, 2, 3, 4, 10, 11, 12, 13, 14}
a.issubset(b)
False
a.issuperset(b)
False